7 * e3= e1+e2 {0, 1, 2, 3, 4}
16 int main(int numargs, char **argv) {
17 CSolver *solver = allocCSolver();
18 uint64_t set1[] = {0, 1, 2};
19 uint64_t setbigarray[] = {0, 1, 2, 3, 4};
21 Set *s = createSet(solver, 0, set1, 3);
22 Set *setbig = createSet(solver, 0, setbigarray, 5);
23 Element *e1 = getElementVar(solver, s);
24 Element *e2 = getElementVar(solver, s);
25 Set *domain[] = {s, s};
26 Predicate *equals = createPredicateOperator(solver, EQUALS, domain, 2);
27 Element *inputs[] = {e1, e2};
28 Boolean *b = applyPredicate(solver, equals, inputs, 2);
29 addConstraint(solver, b);
31 uint64_t set2[] = {2, 3};
32 Set *rangef1 = createSet(solver, 1, set2, 2);
33 Function *f1 = createFunctionOperator(solver, ADD, domain, 2, setbig, IGNORE);
35 Table *table = createTable(solver, domain, 2, s);
36 uint64_t row1[] = {0, 1};
37 uint64_t row2[] = {1, 1};
38 uint64_t row3[] = {2, 1};
39 uint64_t row4[] = {2, 2};
40 addTableEntry(solver, table, row1, 2, 0);
41 addTableEntry(solver, table, row2, 2, 0);
42 addTableEntry(solver, table, row3, 2, 2);
43 addTableEntry(solver, table, row4, 2, 2);
44 Function *f2 = completeTable(solver, table, IGNOREBEHAVIOR); //its range would be as same as s
45 Boolean *overflow = getBooleanVar(solver, 2);
46 Element *e3 = applyFunction(solver, f1, inputs, 2, overflow);
47 Element *e4 = applyFunction(solver, f2, inputs, 2, overflow);
48 Set *domain2[] = {s,rangef1};
49 Predicate *equal2 = createPredicateOperator(solver, EQUALS, domain2, 2);
50 Element *inputs2 [] = {e4, e3};
51 Boolean *pred = applyPredicate(solver, equal2, inputs2, 2);
52 addConstraint(solver, pred);
54 if (startEncoding(solver) == 1)
55 printf("e1=%llu e2=%llu\n", getElementValue(solver,e1), getElementValue(solver, e2));