return false;
}
-/// WillNotOverflowUnsignedAdd - Return true if we can prove that:
-/// (zext (add LHS, RHS)) === (add (zext LHS), (zext RHS))
-bool InstCombiner::WillNotOverflowUnsignedAdd(Value *LHS, Value *RHS,
- Instruction *CxtI) {
- // There are different heuristics we can use for this. Here is a simple one.
- // If the sign bit of LHS and that of RHS are both zero, no unsigned wrap.
- bool LHSKnownNonNegative, LHSKnownNegative;
- bool RHSKnownNonNegative, RHSKnownNegative;
- ComputeSignBit(LHS, LHSKnownNonNegative, LHSKnownNegative, /*Depth=*/0, CxtI);
- ComputeSignBit(RHS, RHSKnownNonNegative, RHSKnownNegative, /*Depth=*/0, CxtI);
- if (LHSKnownNonNegative && RHSKnownNonNegative)
- return true;
-
- return false;
-}
-
/// \brief Return true if we can prove that:
/// (sub LHS, RHS) === (sub nsw LHS, RHS)
/// This basically requires proving that the add in the original type would not
Changed = true;
I.setHasNoSignedWrap(true);
}
- if (!I.hasNoUnsignedWrap() && WillNotOverflowUnsignedAdd(LHS, RHS, &I)) {
+ if (!I.hasNoUnsignedWrap() &&
+ computeOverflowForUnsignedAdd(LHS, RHS, &I) ==
+ OverflowResult::NeverOverflows) {
Changed = true;
I.setHasNoUnsignedWrap(true);
}