+ // Otherwise we can only handle this if it is affine.
+ if (!AddRec->isAffine())
+ return getCouldNotCompute();
+
+ // If this is an affine expression, the execution count of this branch is
+ // the minimum unsigned root of the following equation:
+ //
+ // Start + Step*N = 0 (mod 2^BW)
+ //
+ // equivalent to:
+ //
+ // Step*N = -Start (mod 2^BW)
+ //
+ // where BW is the common bit width of Start and Step.
+
+ // Get the initial value for the loop.
+ const SCEV *Start = getSCEVAtScope(AddRec->getStart(), L->getParentLoop());
+ const SCEV *Step = getSCEVAtScope(AddRec->getOperand(1), L->getParentLoop());
+
+ // For now we handle only constant steps.
+ //
+ // TODO: Handle a nonconstant Step given AddRec<NUW>. If the
+ // AddRec is NUW, then (in an unsigned sense) it cannot be counting up to wrap
+ // to 0, it must be counting down to equal 0. Consequently, N = Start / -Step.
+ // We have not yet seen any such cases.
+ const SCEVConstant *StepC = dyn_cast<SCEVConstant>(Step);
+ if (StepC == 0)
+ return getCouldNotCompute();
+
+ // For positive steps (counting up until unsigned overflow):
+ // N = -Start/Step (as unsigned)
+ // For negative steps (counting down to zero):
+ // N = Start/-Step
+ // First compute the unsigned distance from zero in the direction of Step.
+ bool CountDown = StepC->getValue()->getValue().isNegative();
+ const SCEV *Distance = CountDown ? Start : getNegativeSCEV(Start);
+
+ // Handle unitary steps, which cannot wraparound.
+ // 1*N = -Start; -1*N = Start (mod 2^BW), so:
+ // N = Distance (as unsigned)
+ if (StepC->getValue()->equalsInt(1) || StepC->getValue()->isAllOnesValue())
+ return Distance;
+
+ // If the recurrence is known not to wraparound, unsigned divide computes the
+ // back edge count. We know that the value will either become zero (and thus
+ // the loop terminates), that the loop will terminate through some other exit
+ // condition first, or that the loop has undefined behavior. This means
+ // we can't "miss" the exit value, even with nonunit stride.
+ //
+ // FIXME: Prove that loops always exhibits *acceptable* undefined
+ // behavior. Loops must exhibit defined behavior until a wrapped value is
+ // actually used. So the trip count computed by udiv could be smaller than the
+ // number of well-defined iterations.
+ if (AddRec->getNoWrapFlags(SCEV::FlagNW))
+ // FIXME: We really want an "isexact" bit for udiv.
+ return getUDivExpr(Distance, CountDown ? getNegativeSCEV(Step) : Step);
+
+ // Then, try to solve the above equation provided that Start is constant.
+ if (const SCEVConstant *StartC = dyn_cast<SCEVConstant>(Start))
+ return SolveLinEquationWithOverflow(StepC->getValue()->getValue(),
+ -StartC->getValue()->getValue(),
+ *this);