--- /dev/null
+package edu.uci.iotproject.comparison.seqalignment;
+
+import edu.uci.iotproject.trafficreassembly.layer3.Conversation;
+import edu.uci.iotproject.analysis.TcpConversationUtils;
+
+import java.util.List;
+import java.util.Map;
+import java.util.stream.Collectors;
+
+/**
+ * TODO add class documentation.
+ *
+ * @author Janus Varmarken
+ */
+public class SequenceExtraction {
+
+
+ private final SequenceAlignment<Integer> mAlignmentAlg;
+
+
+ public SequenceExtraction() {
+ mAlignmentAlg = new SequenceAlignment<>(new AlignmentPricer<>((i1,i2) -> Math.abs(i1-i2), i -> 10));
+ }
+
+
+ public SequenceExtraction(SequenceAlignment<Integer> alignmentAlgorithm) {
+ mAlignmentAlg = alignmentAlgorithm;
+ }
+
+ /**
+ * Gets the {@link SequenceAlignment} used to perform the sequence extraction.
+ * @return the {@link SequenceAlignment} used to perform the sequence extraction.
+ */
+ public SequenceAlignment<Integer> getAlignmentAlgorithm() {
+ return mAlignmentAlg;
+ }
+
+ // Initial
+// /**
+// *
+// * @param convsForAction A set of {@link Conversation}s known to be associated with a single type of user action.
+// */
+// public void extract(List<Conversation> convsForAction) {
+// int maxDifference = 0;
+//
+// for (int i = 0; i < convsForAction.size(); i++) {
+// for (int j = i+1; j < convsForAction.size(); i++) {
+// Integer[] sequence1 = getPacketLengthSequence(convsForAction.get(i));
+// Integer[] sequence2 = getPacketLengthSequence(convsForAction.get(j));
+// int alignmentCost = mAlignmentAlg.calculateAlignment(sequence1, sequence2);
+// if (alignmentCost > maxDifference) {
+// maxDifference = alignmentCost;
+// }
+// }
+// }
+//
+// }
+
+
+// public void extract(Map<String, List<Conversation>> hostnameToConvs) {
+// int maxDifference = 0;
+//
+// for (int i = 0; i < convsForAction.size(); i++) {
+// for (int j = i+1; j < convsForAction.size(); i++) {
+// Integer[] sequence1 = getPacketLengthSequence(convsForAction.get(i));
+// Integer[] sequence2 = getPacketLengthSequence(convsForAction.get(j));
+// int alignmentCost = mAlignmentAlg.calculateAlignment(sequence1, sequence2);
+// if (alignmentCost > maxDifference) {
+// maxDifference = alignmentCost;
+// }
+// }
+// }
+//
+// }
+
+ // Building signature from entire sequence
+ public ExtractedSequence extract(List<Conversation> convsForActionForHostname) {
+ // First group conversations by packet sequences.
+ // TODO: the introduction of SYN/SYNACK, FIN/FINACK and RST as part of the sequence ID may be undesirable here
+ // as it can potentially result in sequences that are equal in terms of payload packets to be considered
+ // different due to differences in how they are terminated.
+ Map<String, List<Conversation>> groupedBySequence =
+ TcpConversationUtils.groupConversationsByPacketSequence(convsForActionForHostname, false);
+
+ // Then get a hold of one of the conversations that gave rise to the most frequent sequence.
+ Conversation mostFrequentConv = null;
+ int maxFrequency = 0;
+ for (Map.Entry<String, List<Conversation>> seqMapEntry : groupedBySequence.entrySet()) {
+ if (seqMapEntry.getValue().size() > maxFrequency) {
+ // Found a more frequent sequence
+ maxFrequency = seqMapEntry.getValue().size();
+ // We just pick the first conversation as the representative conversation for this sequence type.
+ mostFrequentConv = seqMapEntry.getValue().get(0);
+ } else if (seqMapEntry.getValue().size() == maxFrequency) {
+ // This sequence has the same frequency as the max frequency seen so far.
+ // Break ties by choosing the longest sequence.
+ // First get an arbitrary representative of currently examined sequence; we just pick the first.
+ Conversation c = seqMapEntry.getValue().get(0);
+ mostFrequentConv = c.getPackets().size() > mostFrequentConv.getPackets().size() ? c : mostFrequentConv;
+ }
+ }
+ // Now find the maximum cost of aligning the most frequent (or, alternatively longest) conversation with the
+ // each of the rest of the conversations also associated with this action and hostname.
+ int maxCost = 0;
+ final Integer[] mostFrequentConvSeq = TcpConversationUtils.getPacketLengthSequence(mostFrequentConv);
+ for (Conversation c : convsForActionForHostname) {
+ if (c == mostFrequentConv) {
+ // Don't compute distance to self.
+ continue;
+ }
+ Integer[] cSeq = TcpConversationUtils.getPacketLengthSequence(c);
+ int alignmentCost = mAlignmentAlg.calculateAlignment(mostFrequentConvSeq, cSeq);
+ if (alignmentCost > maxCost) {
+ maxCost = alignmentCost;
+ }
+ }
+ return new ExtractedSequence(mostFrequentConv, maxCost, false);
+ }
+
+ // Building signature from only TLS Application Data packets
+ public ExtractedSequence extractByTlsAppData(List<Conversation> convsForActionForHostname) {
+ // TODO: temporary hack to avoid 97-only conversations for dlink plug. We need some preprocessing/data cleaning.
+ convsForActionForHostname = convsForActionForHostname.stream().filter(c -> c.getTlsApplicationDataPackets().size() > 1).collect(Collectors.toList());
+
+ Map<String, List<Conversation>> groupedByTlsAppDataSequence =
+ TcpConversationUtils.groupConversationsByTlsApplicationDataPacketSequence(convsForActionForHostname);
+ // Get a Conversation representing the most frequent TLS application data sequence.
+ Conversation mostFrequentConv = groupedByTlsAppDataSequence.values().stream().max((l1, l2) -> {
+ // The frequency of a conversation with a specific packet sequence is the list size as that represents how
+ // many conversations exhibit that packet sequence.
+ // Hence, the difference between the list sizes can be used directly as the return value of the Comparator.
+ // Note: we break ties by choosing the one with the most TLS application data packets (i.e., the longest
+ // sequence) in case the frequencies are equal.
+ int diff = l1.size() - l2.size();
+ return diff != 0 ? diff : l1.get(0).getTlsApplicationDataPackets().size() - l2.get(0).getTlsApplicationDataPackets().size();
+ }).get().get(0); // Just pick the first as a representative of the most frequent sequence.
+ // Lengths of TLS Application Data packets in the most frequent (or most frequent and longest) conversation.
+ Integer[] mostFreqSeq = TcpConversationUtils.getPacketLengthSequenceTlsAppDataOnly(mostFrequentConv);
+ // Now find the maximum cost of aligning the most frequent (or, alternatively longest) conversation with the
+ // each of the rest of the conversations also associated with this action and hostname.
+ int maxCost = 0;
+ for (Conversation c : convsForActionForHostname) {
+ if (c == mostFrequentConv) continue;
+ int cost = mAlignmentAlg.calculateAlignment(mostFreqSeq, TcpConversationUtils.getPacketLengthSequenceTlsAppDataOnly(c));
+ maxCost = cost > maxCost ? cost : maxCost;
+ }
+ return new ExtractedSequence(mostFrequentConv, maxCost, true);
+ // Now find the maximum cost of aligning the most frequent (or, alternatively longest) conversation with the
+ // each of the rest of the conversations also associated with this action and hostname.
+ }
+
+}