1. Fix a carry out problem in add if destination and x point to the same

   memory (as done in fromString).
2. Implement Knuth divide more closely to what is recommended in his book.
3. Fix computation of the remainder for Knuth Divide (bad shifting).
4. Remove some cruft from the file

git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@34518 91177308-0d34-0410-b5e6-96231b3b80d8

diff --git a/lib/Support/APInt.cpp b/lib/Support/APInt.cpp
index 03652a8f8931719b2433e8c790c1defb7d5b7bbe..b84997e8db49a3de60f10a0621674c4d2d933c6b 100644 (file)
--- a/lib/Support/APInt.cpp
+++ b/lib/Support/APInt.cpp
@@ -190,10 +190,10 @@ APInt& APInt::operator--() {
 /// add - This function adds the integer array x[] by integer array
 /// y[] and returns the carry.
 static uint64_t add(uint64_t dest[], uint64_t x[], uint64_t y[], uint32_t len) {
-  uint64_t carry = 0;
+  bool carry = 0;
   for (uint32_t i = 0; i< len; ++i) {
+    uint64_t limit = std::min(x[i],y[i]); // must come first in case dest == x
     dest[i] = x[i] + y[i] + carry;
-    uint64_t limit = std::min(x[i],y[i]);
     carry = dest[i] < limit || (carry && dest[i] == limit);
   }
   return carry;
@@ -979,65 +979,6 @@ APInt APInt::shl(uint32_t shiftAmt) const {
   return API;
 }
 
-#if 0
-/// subMul - This function substracts x[len-1:0] * y from 
-/// dest[offset+len-1:offset], and returns the most significant 
-/// word of the product, minus the borrow-out from the subtraction.
-static uint32_t subMul(uint32_t dest[], uint32_t offset, 
-                        uint32_t x[], uint32_t len, uint32_t y) {
-  uint64_t yl = (uint64_t) y & 0xffffffffL;
-  uint32_t carry = 0;
-  uint32_t j = 0;
-  do {
-    uint64_t prod = ((uint64_t) x[j] & 0xffffffffUL) * yl;
-    uint32_t prod_low = (uint32_t) prod;
-    uint32_t prod_high = (uint32_t) (prod >> 32);
-    prod_low += carry;
-    carry = (prod_low < carry ? 1 : 0) + prod_high;
-    uint32_t x_j = dest[offset+j];
-    prod_low = x_j - prod_low;
-    if (prod_low > x_j) ++carry;
-    dest[offset+j] = prod_low;
-  } while (++j < len);
-  return carry;
-}
-
-/// unitDiv - This function divides N by D, 
-/// and returns (remainder << 32) | quotient.
-/// Assumes (N >> 32) < D.
-static uint64_t unitDiv(uint64_t N, uint32_t D) {
-  uint64_t q, r;                   // q: quotient, r: remainder.
-  uint64_t a1 = N >> 32;           // a1: high 32-bit part of N.
-  uint64_t a0 = N & 0xffffffffL;   // a0: low 32-bit part of N
-  if (a1 < ((D - a1 - (a0 >> 31)) & 0xffffffffL)) {
-      q = N / D;
-      r = N % D;
-  }
-  else {
-    // Compute c1*2^32 + c0 = a1*2^32 + a0 - 2^31*d
-    uint64_t c = N - ((uint64_t) D << 31);
-    // Divide (c1*2^32 + c0) by d
-    q = c / D;
-    r = c % D;
-    // Add 2^31 to quotient 
-    q += 1 << 31;
-  }
-
-  return (r << 32) | (q & 0xFFFFFFFFl);
-}
-
-#endif
-
-/// div - This is basically Knuth's formulation of the classical algorithm.
-/// Correspondance with Knuth's notation:
-/// Knuth's u[0:m+n] == zds[nx:0].
-/// Knuth's v[1:n] == y[ny-1:0]
-/// Knuth's n == ny.
-/// Knuth's m == nx-ny.
-/// Our nx == Knuth's m+n.
-/// Could be re-implemented using gmp's mpn_divrem:
-/// zds[nx] = mpn_divrem (&zds[ny], 0, zds, nx, y, ny).
-
 /// Implementation of Knuth's Algorithm D (Division of nonnegative integers)
 /// from "Art of Computer Programming, Volume 2", section 4.3.1, p. 272. The
 /// variables here have the same names as in the algorithm. Comments explain
@@ -1089,32 +1030,42 @@ static void KnuthDiv(uint32_t *u, uint32_t *v, uint32_t *q, uint32_t* r,
     // on v[n-2] determines at high speed most of the cases in which the trial
     // value qp is one too large, and it eliminates all cases where qp is two 
     // too large. 
-    uint64_t qp = ((uint64_t(u[j+n]) << 32) | uint64_t(u[j+n-1])) / v[n-1];
-    uint64_t rp = ((uint64_t(u[j+n]) << 32) | uint64_t(u[j+n-1])) % v[n-1];
+    uint64_t dividend = ((uint64_t(u[j+n]) << 32) + u[j+n-1]);
+    uint64_t qp = dividend / v[n-1];
+    uint64_t rp = dividend % v[n-1];
     if (qp == b || qp*v[n-2] > b*rp + u[j+n-2]) {
       qp--;
       rp += v[n-1];
-    }
-    if (rp < b) 
-      if (qp == b || qp*v[n-2] > b*rp + u[j+n-2]) {
-        qp--;
-        rp += v[n-1];
+      if (rp < b) {
+        if (qp == b || qp*v[n-2] > b*rp + u[j+n-2]) {
+          qp--;
+          rp += v[n-1];
+        }
       }
+    }
 
-    // D4. [Multiply and subtract.] Replace u with u - q*v (for each word).
-    uint32_t borrow = 0;
-    for (uint32_t i = 0; i < n; i++) {
-      uint32_t save = u[j+i];
-      u[j+i] = uint64_t(u[j+i]) - (qp * v[i]) - borrow;
-      if (u[j+i] > save) {
-        borrow = 1;
-        u[j+i+1] += b;
-      } else {
-        borrow = 0;
-      }
+    // D4. [Multiply and subtract.] Replace (u[j+n]u[j+n-1]...u[j]) with
+    // (u[j+n]u[j+n-1]..u[j]) - qp * (v[n-1]...v[1]v[0]). This computation
+    // consists of a simple multiplication by a one-place number, combined with
+    // a subtraction. The digits (u[j+n]...u[j]) should be kept positive;
+    bool borrow = 0;
+    for (uint32_t i = 0; i < n; ++i) {
+      uint64_t u_tmp = borrow ? u[j+i] - 1 : u[j+i];
+      uint64_t subtrahend = qp * v[i];
+      borrow = subtrahend > u_tmp || (borrow && u[j+i] == 0);
+      u[j+i] = u_tmp - subtrahend;
+    }
+    // if the result of this step is actually negative, (u[j+n]...u[j]) should
+    // be left as the true value plus b**(n+1), names as the b's complement of
+    // the true value, and a "borrow" to the left should be remembered.
+    //
+    if (borrow) {
+      borrow = u[j+n] == 0;
+      u[j+n]--;
+//      for (uint32_t i = 0; i < n; ++i) {
+//        u[j+i] = ~u[j+i] + 1; // b's complement
+//      }
     }
-    if (borrow)
-      u[j+n] += 1;
 
     // D5. [Test remainder.] Set q[j] = qp. If the result of step D4 was 
     // negative, go to step D6; otherwise go on to step D7.
@@ -1122,20 +1073,22 @@ static void KnuthDiv(uint32_t *u, uint32_t *v, uint32_t *q, uint32_t* r,
     if (borrow) {
       // D6. [Add back]. The probability that this step is necessary is very 
       // small, on the order of only 2/b. Make sure that test data accounts for
-      // this possibility. Decreate qj by 1 and add v[...] to u[...]. A carry 
-      // will occur to the left of u[j+n], and it should be ignored since it 
-      // cancels with the borrow that occurred in D4.
-      uint32_t carry = 0;
+      // this possibility. Decrease q[j] by 1 
+      q[j]--;
+      // and add (0v[n-1]...v[1]v[0]) to (u[j+n]u[j+n-1]...u[j+1]u[j]). 
+      // A carry will occur to the left of u[j+n], and it should be ignored 
+      // since it cancels with the borrow that occurred in D4.
+      bool carry = false;
       for (uint32_t i = 0; i < n; i++) {
         uint32_t save = u[j+i];
         u[j+i] += v[i] + carry;
-        carry = u[j+i] < save;
+        uint32_t limit = std::min(save,v[i]);
+        carry = u[j+i] < limit || (carry && u[j+1] == limit);
       }
     }
 
-    // D7. [Loop on j.]  Decreate j by one. Now if j >= 0, go back to D3.
-    j--;
-  } while (j >= 0);
+  // D7. [Loop on j.]  Decrease j by one. Now if j >= 0, go back to D3.
+  } while (--j >= 0);
 
   // D8. [Unnormalize]. Now q[...] is the desired quotient, and the desired
   // remainder may be obtained by dividing u[...] by d. If r is non-null we
@@ -1144,12 +1097,10 @@ static void KnuthDiv(uint32_t *u, uint32_t *v, uint32_t *q, uint32_t* r,
     // The value d is expressed by the "shift" value above since we avoided
     // multiplication by d by using a shift left. So, all we have to do is
     // shift right here. In order to mak
-    uint32_t mask = ~0u >> (32 - shift);
     uint32_t carry = 0;
     for (int i = n-1; i >= 0; i--) {
-      uint32_t save = u[i] & mask;
       r[i] = (u[i] >> shift) | carry;
-      carry = save;
+      carry = u[i] << shift;
     }
   }
 }