number of them.</p>
</ul>
<p>
-Initially each layout will possess a direct pointer to the
+As of v2.4 each layout still possesses a direct pointer to the
start of the array of <tt>Use</tt>s. Though not mandatory for layout a),
we stick to this redundancy for the sake of simplicity.
-The <tt>User</tt> object will also store the number of <tt>Use</tt> objects it
+The <tt>User</tt> object also stores the number of <tt>Use</tt> objects it
has. (Theoretically this information can also be calculated
given the scheme presented below.)</p>
<p>
Special forms of allocation operators (<tt>operator new</tt>)
-will enforce the following memory layouts:</p>
+enforce the following memory layouts:</p>
<ul>
-<li><p>Layout a) will be modelled by prepending the <tt>User</tt> object by the <tt>Use[]</tt> array.</p>
+<li><p>Layout a) is modelled by prepending the <tt>User</tt> object by the <tt>Use[]</tt> array.</p>
<pre>
...---.---.---.---.-------...
'''---'---'---'---'-------'''
</pre>
-<li><p>Layout b) will be modelled by pointing at the Use[] array.</p>
+<li><p>Layout b) is modelled by pointing at the <tt>Use[]</tt> array.</p>
<pre>
.-------...
| User
<div class="doc_text">
<p>
-Since the <tt>Use</tt> objects will be deprived of the direct pointer to
+Since the <tt>Use</tt> objects are deprived of the direct (back)pointer to
their <tt>User</tt> objects, there must be a fast and exact method to
recover it. This is accomplished by the following scheme:</p>
</div>
-A bit-encoding in the 2 LSBits (least significant bits) of the <tt>Use::Prev</tt> will allow to find the
+A bit-encoding in the 2 LSBits (least significant bits) of the <tt>Use::Prev</tt> allows to find the
start of the <tt>User</tt> object:
<ul>
<li><tt>00</tt> —> binary digit 0</li>
new <tt>Use**</tt> on every modification. Accordingly getters must strip the
tag bits.</p>
<p>
-For layout b) instead of the <tt>User</tt> we will find a pointer (<tt>User*</tt> with LSBit set).
-Following this pointer brings us to the <tt>User</tt>. A portable trick will ensure
-that the first bytes of <tt>User</tt> (if interpreted as a pointer) will never have
+For layout b) instead of the <tt>User</tt> we find a pointer (<tt>User*</tt> with LSBit set).
+Following this pointer brings us to the <tt>User</tt>. A portable trick ensures
+that the first bytes of <tt>User</tt> (if interpreted as a pointer) never has
the LSBit set.</p>
</div>