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Use call site mergeWith method to simplify code
author
Chris Lattner
<sabre@nondot.org>
Mon, 11 Nov 2002 00:00:46 +0000
(
00:00
+0000)
committer
Chris Lattner
<sabre@nondot.org>
Mon, 11 Nov 2002 00:00:46 +0000
(
00:00
+0000)
git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@4687
91177308
-0d34-0410-b5e6-
96231b3b80d8
lib/Analysis/DataStructure/DataStructure.cpp
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diff --git
a/lib/Analysis/DataStructure/DataStructure.cpp
b/lib/Analysis/DataStructure/DataStructure.cpp
index 67778181ef18f273b382f8a95aeef0d3b8b78604..b07a0f7d8541120577bb32730d4a1cceff62bf93 100644
(file)
--- a/
lib/Analysis/DataStructure/DataStructure.cpp
+++ b/
lib/Analysis/DataStructure/DataStructure.cpp
@@
-830,12
+830,8
@@
static void removeIdenticalCalls(vector<DSCallSite> &Calls,
// FIXME: Evaluate how many times this is tripped!
NumDuplicateCalls > 20) {
DSCallSite &OCS = Calls[i-1];
- OCS.
getRetVal().mergeWith(CS.getRetVal()
);
+ OCS.
mergeWith(CS
);
- for (unsigned a = 0,
- e = std::min(CS.getNumPtrArgs(), OCS.getNumPtrArgs());
- a != e; ++a)
- OCS.getPtrArg(a).mergeWith(CS.getPtrArg(a));
// The node will now be eliminated as a duplicate!
if (CS.getNumPtrArgs() < OCS.getNumPtrArgs())
CS = OCS;